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y=sin(2x+1),求导函数

解: 令f(x)=y=sin(2x+1) f'(x)=[sin(2x+1)]' =cos(2x+1)·(2x+1)' =cos(2x+1)·2 =2cos(2x+1) 函数的导函数为y=2cos(2x+1)

复合函数求导公式

y = [sin(2x+1)]^2 y ' = 2sin(2x+1)*cos(2x+1)*2 = 2sin(4x+2)

y=xsin2x y'=x'sin2x+xsin'2x y'=sin2x+2xcos2x

计算过程如下: y=sin2x+1 y'=cos2x*2=2cos2x 所以: y'(π/2)=2cosπ=-2.

dy/dx=(sinxcosx)/(根号下1+sin^2x)

f(x)=x-⅓sin2x+asinx f'(x)=1-⅓cos2x·(2x)'+acosx =1-⅔cos2x+acosx

你看看下面的MATLAB语句也许就明白了 >> syms x L vpa(subs(diff(sin(x)),x,L)) ans = cos(L) >> syms x vpa(subs(diff(sin(x)),x,5)) ans = 0.28366218546322624627364916705119 >> syms x subs(diff(sin(x)),x,5) ans = 0.2837 vpa(式子, 变...

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