www.fltk.net > Cos80°Cos35°+Cos10°Cos55°=______

Cos80°Cos35°+Cos10°Cos55°=______

∵cos80°cos35°+cos10°cos55°=cos80°cos35°+sin80°sin35°=cos(80°-35°)=cos45°= 2 2 .故答案为: 2 2 .

∵cos80°cos35°+cos10°cos55°=cos80°cos35°+sin80°sin35°=cos(80°-35°)=cos45°=22.故答案为:22.

原式=sin10 ° cos35 ° +cos10 ° sin35 ° =sin(10 ° +35 ° )=sin45 ° = 2 2

原式=sin10 ° cos35 ° +cos10 ° sin35 ° =sin(10 ° +35 ° )=sin45 ° = 2 2

sin80°cos55°+cos80°cos35°=cos10°cos55°+sin10°sin55°=cos(55°-10°)=cos45°=22,故答案为 22.

cos80cos35+cos10cos55=sin10cos35+cos10sin35=sin45=根号2/2 cossin10 cos35 + cos10 sin35 =sin45 =√2/2 希望我的回答对你有

原式=sin80º•sin(90º-35º) + cos80º•sin35º =sin80º•cos35º + cos80º•sin35º =sin(80º+35º) =sin115º =sin(90º+25º) =sin25º

sin80°cos35°-cos80°sin35° =sin(80-35) =sin45 =√2/2

(sin^2(35°)-1/2)/cos10°cos80° =cos70°/2cos10°cos80° =cos70°/(cos90°+cos70°) =1

cos80°cos130°—cos10°sin130° =cos80°cos130°—sin(90-10)°sin130° =cos80°cos130°—sin80°sin130° =cos(80+130)° =cos210° =-√3/2

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