www.fltk.net > (1)计算:2log 3 2%log 3 32 9 +log 3 8% ...

(1)计算:2log 3 2%log 3 32 9 +log 3 8% ...

(1)2log 3 2-log 3 32 9 +log 3 8-25 log

-21.853209118683

2log3 2-log32/9+log3 8-5^log5 3 =2log3 2-log3 2+

-1

最终答案:71/12

(1)∵函数f(x)=log3(9x)?log3(3x),且19≤x≤9.∴f(3)=log3(9×

用换底公式 原式=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9) =(lg

用换底公式 原式=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9)-lg32/

2log₃ 2-log₃(32/9)+logS

log以根号3为底2-log以3为底32/9+log以3为底8-25(log以5为底3)次方 =l

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